JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1

The solution of the equation

\,{\left( {3 + 2\sqrt 2 } \right)^{{x^2} - 8}} + {\left( {3 + 2\sqrt 2 } \right)^{8 - {x^2}}} = 6

are

View answer and explanation

Correct option: D

\pm 3,\; \pm \sqrt 7

Option D (

\pm 3,\\; \pm \sqrt 7

) is correct because by substituting

y = {\left( {3 + 2\sqrt 2 } \right)^{{x^2} - 8}}

and solving the quadratic equation, we find the possible values of x.

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