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JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1
Let α,β\alpha, \beta be the roots of the equation x2−2x+2=0x^{2}-\sqrt{2} x+2=0. Then α14+β14\alpha^{14}+\beta^{14} is equal to
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Correct option: C
−128-128
Option C (-128) is correct because after finding the roots in polar form and raising them to the power of 14, the sum simplifies to -128.

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