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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy
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Analyzing +4 | -1
If a,  b,  ca,\;b,\;c be positive real number and the value of

θ=tan⁡−1a(a+b+c)bc+tan⁡−1b(a+b+c)ca+tan⁡−1c(c+b+c)ab\mathrm{\theta } = {\tan ^{ - 1}}\sqrt {\frac{{a\left( {a + b + c} \right)}}{{bc}}} + {\tan ^{ - 1}}\sqrt {\frac{{b\left( {a + b + c} \right)}}{{ca}}} + {\tan ^{ - 1}}\sqrt {\frac{{c\left( {c + b + c} \right)}}{{ab}}}

Then tan θ\mathrm{\theta } is equal to
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Correct option: A
0
Option A (0) is correct because after substituting and simplifying, the expression inside the tangent function becomes zero, resulting in tan θ = 0.

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