JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

\mathrm{x}=\frac{\mathrm{t}-\mathrm{e}^{-\mathrm{t}^2}}{2 \mathrm{t}^2}

, then

\left(\mathrm{t} \frac{\mathrm{dx}}{\mathrm{dt}}-\mathrm{e}^{-\mathrm{t}^2}\right)=

View answer and explanation

Correct option: A

\frac{1}{2 \mathrm{t}}-2 \mathrm{x}

Option A (

\frac{1}{2 \mathrm{t}}-2 \mathrm{x}

) is correct because it's the result of correctly differentiating x with respect to t and then substituting back the original expression for x.

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