JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

f(x)=\cos \left(x^2-4[x]\right)

for

0 < x < 1

, where

[x]=

G.I.F

., then

f^{\prime}\left(\frac{\sqrt{\pi}}{2}\right)

is equal to

View answer and explanation

Correct option: A

-\sqrt{\frac{\pi}{2}}

Option A (

-\sqrt{\frac{{\pi}}{{2}}}

) is correct because it is the value of the derivative of the function at the given point.

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