JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Analyzing +4 | -1

a + b + c = 0

and

a \ne c

then the roots of the equation

\left( {b + c - a} \right){x^2} + \left( {c + a - b} \right)x + \left( {a + b - c} \right) = 0,

are

View answer and explanation

Correct option: A

Real and unequal

Option A (Real and unequal) is correct because the discriminant of the quadratic equation is positive, indicating two distinct real roots.

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{x^2} - px + q = 0

{\alpha _1},{\beta _1}

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{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

\;f\left( { - 1} \right) < 1,f\left( 1 \right) > - 1,f\left( 3 \right) < - 4\;

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9{x^2} - 18\left| x \right| + 5 = 0

f\left( x \right) = \log \left( {{x^2} - x - 2} \right)