JEE MATHEMATICS MCQ: DIFFERENTIATION

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f(x)=(1+x)^{n }

, then

f(0)+f(0)+\frac{1}{2} f^{\prime}(0)+\ldots+\frac{1}{n !} f^n(0)=\ldots \ldots

View answer and explanation

Correct option: B

2^n

Option B (

2^n

) is correct because the given expression is the binomial expansion of

(1+1)^n

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