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JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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A coil of 1200 turns and mean area of 500  cm2500\,\,\mathrm{c}{\mathrm{m}^2} is held perpendicular to a uniform magnetic field of induction 4×10−4  T.4 \times {10^{ - 4}}\,\,\mathrm{T}. The resistance of the coil is 20 ohm. When the coil is rotated through 1800{180^0} in the magnetic field is 0.1 seconds the average electric current (in MA) induced is
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Correct option: B
0.24
Option B (0.24) is correct because the average electric current is calculated using the formula derived from Faraday's law of electromagnetic induction.

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