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JEE MATHEMATICS MCQ: DIFFERENTIATION

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If xy=ax2+(b/x)x y=a x^2+(b / x), then xd2ydx2+2dydx=x \frac{d^2 y}{d x^2}+2 \frac{d y}{d x}=
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Correct option: C
2yx\frac{2 y}{x}
Option C (2yx\frac{{2 y}}{{x}}) is correct because after differentiating the given equation twice and simplifying, the expression xd2ydx2+2dydxx \frac{{d^2 y}}{{d x^2}}+2 \frac{{d y}}{{d x}} simplifies to 2yx\frac{{2 y}}{{x}}.

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