JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

\mathrm{y}=\left(\sin ^{-1} \mathrm{x}\right)^2+\left(\cos ^{-1} \mathrm{x}\right)^2

, then

\left(1-\mathrm{x}^2\right) \mathrm{y_2-x y_1}=

View answer and explanation

Correct option: B

Option B (4) is correct because, after differentiating the given equation twice and simplifying, the expression (1-x²)y_2 - xy_1 equals 4.

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