JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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Analyzing +4 | -1

Following is the relation between current and charge

I = A{T^2}{e^{q/{V_L}}}

, then value of

{V_L}

will be

View answer and explanation

Correct option: C

\frac{{kT}}{V}

Option C (

\frac{{kT}}{{V}}

) is correct because by comparing the given equation with the standard equation, we can directly derive the value of

V_L

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