JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Hard

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Analyzing +4 | -1

The solution of the quadratic equation

{\left( {3\left| x \right| - 3} \right)^2} = \left| x \right| + 7

which belongs to the domain of definition of the function

y = \sqrt {x\left( {x - 3} \right)}

are given by

View answer and explanation

Correct option: D

- \frac{1}{9},\; - 2

Option D (

- \frac{1}{9},\; - 2

) is correct because these are the only solutions to the quadratic equation that also satisfy the domain of the function

y = \sqrt {x(x - 3)}

More Questions from QUADRATIC EQUATIONS

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\log _7 \log _5(\sqrt{x+5}+\sqrt{x})=0

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{x^2} - 3x + a = 0,a \in R

\alpha < 1 < \beta ,

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{x^2} - px + q = 0

{\alpha _1},{\beta _1}

{x^2} - qx + p = 0,

\frac{1}{{{\alpha _1}\beta }} + \frac{1}{{\alpha {\beta _1}}}\mathrm{and}\;\frac{1}{{\alpha {\alpha _1}}} + \frac{1}{{\beta {\beta _1}}},

{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

\;f\left( { - 1} \right) < 1,f\left( 1 \right) > - 1,f\left( 3 \right) < - 4\;

\;a \ne 0,

9{x^2} - 18\left| x \right| + 5 = 0

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