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JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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The input resistance of a CE amplifier is 5kΩ5 \mathrm{k \Omega} and the load resistance is 20kΩ20 \mathrm{k} \Omega. If the current gain is 100 then mutual conductance of the transistor used is
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Correct option: C
20×10−3Ω−120 \times 10^{-3} \Omega^{-1}
Option C (20×10−3Ω−120 \times 10^{-3} \Omega^{-1}) is correct because the mutual conductance is the ratio of the current gain to the input resistance.

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