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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1
If f(x)f(x) and g(x)g(x) are two functions from R\mathbb{R} to R\mathbb{R} such that (f∘g)(x)=(x3βˆ’x2+2)8(f \circ g)(x)=\left(x^3-x^2+2\right)^8, then fβ€²(1)gβ€²(1)f^{\prime}(1) g^{\prime}(1) is
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Correct option: A
8
Option A (8) is correct because, by choosing f(x)=x8f(x) = x^8 and g(x)=x3βˆ’x2+2g(x) = x^3 - x^2 + 2, we get (f∘g)(x)=(x3βˆ’x2+2)8(f \circ g)(x) = (x^3 - x^2 + 2)^8. Then, fβ€²(1)=8f'(1) = 8 and gβ€²(1)=1g'(1) = 1, so fβ€²(1)gβ€²(1)=8f'(1)g'(1) = 8.

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