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JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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The series combination of resistance RR and inductance LL is connected to an alternating source of emf e=311 sin⁡(100πt). e = 311\,\sin (100\pi t).\, If the value of wattles current is 0.5 A and the impedance of the circuit is 311 Ω311\,\Omega, the power factor will be:-
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Correct option: B
12\frac{1}{{\sqrt 2 }}
Option B (12\frac{{1}}{{\sqrt 2 }}) is correct because the power factor is the cosine of the phase angle, which can be derived from the given wattless current and impedance.

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