If $y=\cot ^{-1}\left(x^2\right)$, then $\frac{d y}{d x}$ is equal to :

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

y=\cot ^{-1}\left(x^2\right)

, then

\frac{d y}{d x}

is equal to :

View answer and explanation

Correct option: C

\frac{-2 x}{1+x^4}

Option C (

\frac{{-2 x}}{{1+x^4}}

) is correct because it is the derivative of arccot(x²) using the chain rule.

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