If $4 \le x \le 9,$ then

$\left( {x - 4} \right)\left( {x - 9} \right) \ge 0$

$\left( {x - 4} \right)\left( {x - 9} \right) < 0$

$\left( {x - 4} \right)\left( {x - 9} \right) > 0$

JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Understanding +4 | -1

4 \le x \le 9,

then

View answer and explanation

Correct option: A

\left( {x - 4} \right)\left( {x - 9} \right) \le 0

Option B (

(x - 4)(x - 9) \ge 0

) is incorrect. Option A (

(x - 4)(x - 9) \le 0

) is correct because for

x

between 4 and 9 inclusive,

(x-4)

is non-negative and

(x-9)

is non-positive, making their product non-positive.

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a

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