JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1

\cot ^{-1} \frac{x y+1}{x-y}+\cot ^{-1} \frac{y z+1}{y-z}+\cot ^{-1} \frac{z x+1}{z-x} ; x > y > z > 0

and

x, y, z

distinct is equal to

View answer and explanation

Correct option: A

Option A (0) is correct because the expression simplifies to 0 using the inverse tangent subtraction formula and the given conditions.

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x

{x^2} + {y^2} + {z^2} = {r^2},

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2{\tan ^{ - 1}}\left( {\frac{1}{3}} \right) + {\tan ^{ - 1}}\left( {\frac{1}{7}} \right)