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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1
If f(x)=(x−2)(x−4)(x−6)…(x−2n),f\left( x \right) = \left( {x - 2} \right)\left( {x - 4} \right)\left( {x - 6} \right) \ldots \left( {x - 2n} \right), thenf′(2)f'\left( 2 \right) is
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Correct option: B
(−2)n−1(n−1)!{\left( { - 2} \right)^{n - 1}}\left( {n - 1} \right)!
Option B ((−2)n−1(n−1)!{(- 2)^{n - 1}}(n - 1)!) is correct because after differentiating the given function and evaluating at x=2, the result is (−2)n−1(n−1)!{(- 2)^{n - 1}}(n - 1)!.

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