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JEE PHYSICS MCQ: ATOMS

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An α\alpha-particle of energy 4 MeV4\,\mathrm{MeV} is scattered by gold foil (Z=79)(Z=79). Calculate the maximum volume in which positive charge of the atom is likely to be concentrated.
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Correct option: A
7.7×10−40 m7.7 \times 10^{-40} \mathrm{~m}
Option A (7.7×10−40 m7.7 \times 10^{-40} \mathrm{~m}) is correct because it's calculated by finding the distance of closest approach and then using that radius to calculate the volume.

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