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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1
If 12sin⁡−1(3sin⁡2θ5+4cos⁡2θ)=π4\frac{1}{2} \sin ^{-1}\left(\frac{3 \sin 2 \theta}{5+4 \cos 2 \theta}\right)=\frac{\pi}{4}, then tan⁡θ\tan \theta is equal to
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Correct option: B
3
Option B (3) is correct because solving the equation after applying the sine function and simplifying leads to tan⁡θ=3\tan \theta = 3.

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