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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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During a heavy rain, hailstones of average size 1.0 cm1.0 \mathrm{~cm} in diameter fall with an average speed of 20 m/s20 \mathrm{~m} / \mathrm{s}. Suppose 2000 hailstones strike every square meter of a 10 m×10 m10 \mathrm{~m} \times 10 \mathrm{~m} roof perpendicularly in one second and assume that the hailstones do not rebound. Calculate the average force exerted by the falling hailstones on the roof. Density of a hailstone is 900 kg/m3900 \mathrm{~kg} / \mathrm{m}^3.
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Correct option: A
1900 N1900 \mathrm{~N}
Option A (1900 N1900 \mathrm{~N}) is correct because it is the average force exerted by the hailstones calculated using the change in momentum.

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