Skip to main content
Back to DIFFERENTIATION

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy
1 of 1
Application +4 | -1
d2xdy2\frac{d^2 x}{d y^2} equals
View answer and explanation
Correct option: A
−(d2ydx2)−1(dydx)−3-\left(\frac{d^2 y}{d x^2}\right)^{-1}\left(\frac{d y}{d x}\right)^{-3}
Option A (−(d2ydx2)−1(dydx)−3-\left(\frac{{d^2 y}}{{d x^2}}\right)^{-1}\left(\frac{{d y}}{{d x}}\right)^{-3}) is correct because it represents the second derivative of x with respect to y in terms of derivatives of y with respect to x.

More Questions from DIFFERENTIATION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.