JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

1 of 1

Application +4 | -1

{\left( {{{\tan }^{ - 1}}x} \right)^2} + {\left( {{{\cot }^{ - 1}}x} \right)^2} = \frac{{5{\pi ^2}}}{8}

, then

x

equals

View answer and explanation

Correct option: A

- 1

Option A (

-1

) is correct because by using the identity

{\tan ^{ - 1}}x + {\cot ^{ - 1}}x = \frac{\pi }{2}

and solving the resulting quadratic equation, we find that

x = -1

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x

{x^2} + {y^2} + {z^2} = {r^2},

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2{\tan ^{ - 1}}\left( {\frac{1}{3}} \right) + {\tan ^{ - 1}}\left( {\frac{1}{7}} \right)