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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1
The range of a∈Ra \in R for which the function
f(x)=(4a−3)(x+log⁡e5)+2(a−7)cot⁡(x2)sin⁡2(x2),  x≠2nπ,  n∈Nf\left( x \right) = \left( {4a - 3} \right)\left( {x + {{\log }_e}5} \right) + 2\left( {a - 7} \right)\cot \left( {\frac{x}{2}} \right){\sin ^2}\left( {\frac{x}{2}} \right),\,\,x \ne 2n\pi ,\,\,n \in N has critical points, is:
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Correct option: A
[−43, 2]\left[ { - \frac{4}{3},\,2} \right]
Option A ([−43, 2]\left[ { - \frac{4}{3},\,2} \right]) is correct because it represents the range of 'a' for which the given function has critical points, derived from the condition -1 <= cos(x) <= 1.

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