The value of sin $({\cot ^{ - 1}}x)$ is

${\left( {1 + {x^2}} \right)^{ - 3/2}}$

JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

1 of 1

Application +4 | -1

The value of sin

({\cot ^{ - 1}}x)

View answer and explanation

Correct option: D

{\left( {1 + {x^2}} \right)^{ - 1/2}}

Option D (

{\left( {1 + {x^2}} \right)^{ - 1/2}}

) is correct because by letting

{\cot ^{ - 1}}x = \mathrm{\theta }

, we can find

\sin{\theta}

in terms of x.

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