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JEE PHYSICS MCQ: ATOMS

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Application +4 | -1
The energy of an electron in the nthn^{th} orbit is given by En=−13.6/n2eVE_n=-13.6 / n^2 \mathrm{eV}. Calculate the energy required to excite an electron from ground state to the second excited state.
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Correct option: A
12.09 eV
Option A (12.09 eV) is correct because it is the energy difference between the ground state and the second excited state.

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