JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Analyzing +4 | -1

The number of real solutions of

{\tan ^{ - 1}}\sqrt {x\left( {x + 1} \right)} + {\sin ^{ - 1}}\sqrt {{x^2} + x + 1} = \frac{\pi }{2}

View answer and explanation

Correct option: C

Option C (2) is correct because the equation simplifies to

{x^2} + x = 0

, which has two real solutions:

x = 0

and

x = -1

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