JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

y=f\left(\frac{2 x-1}{x^2+1}\right)

and

f^{\prime}(x)=\sin x^2

, then

\frac{d y}{d x}

is equal to

View answer and explanation

Correct option: B

\sin \left(\frac{2 x-1}{x^2+1}\right)^2\left\{\frac{2+2 x-2 x^2}{\left(x^2+1\right)^2}\right\}

Option B is correct because it correctly applies the chain rule and quotient rule to find the derivative of the given function.

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