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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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Application +4 | -1
A gun fires bullet each of mass 1 g with velocity of 10  ms−110\;\mathrm{m}{\mathrm{s}^{ - 1}} by exerting a constant force of 5 g weight. Then the number of bullets fired per second is (Take g=10  ms−2)g = 10\;\mathrm{m}{\mathrm{s}^{ - 2}})
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Correct option: B
5
Option B (5) is correct because the number of bullets fired per second is calculated using the formula derived from the rate of change of linear momentum.

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