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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy
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Application +4 | -1
If 12≤x≤1\frac{1}{2} \le x \le 1, then sin⁡−1(3x−4x3){\sin ^{ - 1}}\left( {3x - 4{x^3}} \right) equals
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Correct option: B
π−3sin⁡−1x\pi - 3{\sin ^{ - 1}}x
Option B (π−3sin⁡−1x\pi - 3{\sin ^{ - 1}}x) is correct because it is the correct simplification of the given expression within the specified range of x, using trigonometric identities.

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