JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

1 Medium

1 of 1

Application +4 | -1

Mutual conductance of triode is

2\mathrm{\;m}{\mathrm{\Omega }^{ - 1}}

and the amplification factor is 50. Its anode is connected with a source of 250 V and a resistance of

25\mathrm{\;k\Omega }

. The voltage gain of this amplifier is

View answer and explanation

Correct option: C

Option C (25) is correct because it is the voltage gain calculated using the given mutual conductance, amplification factor, anode voltage, and resistance.

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