JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

1 of 1

Application +4 | -1

\sum\limits_{r\, = \,1}^{50} {{{\tan }^{ - 1}}\frac{1}{{2{r^2}}} = p}

, then the value of the

\tan \,p

View answer and explanation

Correct option: B

\frac{{50}}{{51}}

Option B (

\frac{{50}}{{51}}

) is correct because it is the tangent of the sum of the arctangent series, which simplifies to a telescoping series.

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2{\tan ^{ - 1}}\left( {\frac{1}{3}} \right) + {\tan ^{ - 1}}\left( {\frac{1}{7}} \right)