JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1

x = {e^t}\sin t,y = {e^t}\cos t,t

is a parameter, then

\frac{{{d^2}y}}{{d{x^2}}}

at (1,1) is equal to

View answer and explanation

Correct option: A

- \frac{1}{2}

The correct answer is A (

- \frac{1}{2}

) because after finding the first and second derivatives using parametric differentiation and substituting

t = \frac{\pi}{4}

, the value of

\frac{d^2y}{dx^2}

at (1,1) is

-\frac{1}{2}

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\frac{{dy}}{{dx}}

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