If $y=\log _{\sin x}(\tan x)$, then $\frac{d y}{d x}$ at $x=\frac{\pi}{4}$ is equal to

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

y=\log _{\sin x}(\tan x)

, then

\frac{d y}{d x}

x=\frac{\pi}{4}

is equal to

View answer and explanation

Correct option: C

\frac{-4}{\log 2}

Option C (

\frac{-4}{\log 2}

) is correct because it is the result of differentiating the logarithmic function and evaluating at

x=\frac{\pi}{4}

Practice All Chapter MCQs →

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x

y

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x+y

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[x]

x

x=k, k

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y = {\sec ^{ - 1}}\left[ {\mathrm{cosec}x} \right] + \mathrm{cose}{\mathrm{c}^{ - 1}}\left[ {\sec x} \right] + {\sin ^{ - 1}}[\cos x] + {\cos ^{ - 1}}[\sin x],

\frac{{dy}}{{dx}}

\frac{d}{d x} \sin ^{-1}\left(3 x-4 x^{3}\right)

z = y + f\left( v \right),

v = \left( {\frac{x}{y}} \right),

v\frac{{\partial z}}{{\partial x}} + \frac{{\partial z}}{{\partial y}}