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JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy
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Application +4 | -1
If x=acos⁡2t,y=bsin⁡2tx=a \cos 2 t, y=b \sin ^2 t then d2ydx2\frac{d^2 y}{d x^2} is equal to
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Correct option: B
0
Option B (0) is correct because after finding the first derivative dy/dx, it results in a constant, and the derivative of a constant is zero.

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