If $ y=\frac{e^{2 x}+e^{-2 x}}{e^{2 x}-e^{-2 x}} $, then $ \frac{d y}{d x} $ is equal to

$ \frac{-4}{\left(e^{2 x}-e^{-2 x}\right)^{2}} $

$ \frac{4}{\left(e^{2 x}-e^{-2 x}\right)^{2}} $

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

y=\frac{e^{2 x}+e^{-2 x}}{e^{2 x}-e^{-2 x}}

, then

\frac{d y}{d x}

is equal to

View answer and explanation

Correct option: A

\frac{-8}{\left(e^{2 x}-e^{-2 x}\right)^{2}}

Option A is correct because the derivative is found using the quotient rule and simplifying the resulting expression.

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