A mass of $1 \mathrm{~kg}$ is acted upon by a single force ${F}=(4 \hat{{i}}+4 \hat{j}) \mathrm{N}$. Under this force, it is displaced from $(0,0)$ to $(1 \mathrm{~m}, 1 \mathrm{~m})$. If initially, the speed of the particle was $2 \mathrm{~ms}^{-1}$, its final speed should be

JEE PHYSICS MCQ: WORK-ENERGY-POWER

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A mass of

1 \mathrm{~kg}

is acted upon by a single force

{F}=(4 \hat{{i}}+4 \hat{j}) \mathrm{N}

. Under this force, it is displaced from

(0,0)

(1 \mathrm{~m}, 1 \mathrm{~m})

. If initially, the speed of the particle was

2 \mathrm{~ms}^{-1}

, its final speed should be

View answer and explanation

Correct option: B

4.5 \mathrm{~ms}^{-1}

Option B (

4.5 \mathrm{~ms}^{-1}

) is correct because it is derived from the work-energy theorem, considering the force and displacement.

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m^{\prime}

v_1