If $f\left( x \right) = {\rm{arc}}\tan \left( {\frac{{{x^x} - {x^{ - x}}}}{2}} \right)$, then $f'\left( 1 \right)$ is equal to

JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1

f\left( x \right) = \mathrm{arc}\tan \left( {\frac{{{x^x} - {x^{ - x}}}}{2}} \right)

, then

f'\left( 1 \right)

is equal to

View answer and explanation

Correct option: D

None of these

Option D (None of these) is correct because the derivative

f'(1)

does not exist due to the function's behavior around

x=1

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