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JEE PHYSICS MCQ: ATOMS

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Potential energy as a function of rr is given by U=Ar10−Br5,U = \frac{A}{{{r^{10}}}} - \frac{B}{{{r^5}}}, where rr is the interatomic distance, A and B are positive constants. The equilibrium distance between the two atoms will be:
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Correct option: C
(2AB)15{\left( {\frac{{2A}}{B}} \right)^{\frac{1}{5}}}
Option C ((2AB)15{\left( {\frac{{2A}}{B}} \right)^{\frac{1}{5}}}) is correct because at equilibrium, the derivative of the potential energy with respect to r is zero, which leads to this expression for r.

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