JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1

x = a\cos \theta ,y = b\sin \theta

, then

\frac{{{d^3}y}}{{d{x^3}}}

is equal to

View answer and explanation

Correct option: C

- \frac{{3b}}{{{a^3}}}\mathrm{cose}{\mathrm{c}^4}\theta \cot \theta

Option D (None of these) is correct. After calculating the derivatives, the correct expression for

\frac{{{{d^3}y}}}{{{{dx^3}}}}

does not match any of the given options.

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