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JEE MATHEMATICS MCQ: DIFFERENTIATION

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If y=axn+1+bx−ny=a x^{n+1}+b x^{-n}, then x2d2ydx2=x^2 \frac{d^2 y}{d x^2}=
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Correct option: B
n(n+1)yn(n+1) y
Option B (n(n+1)yn(n+1) y) is correct because it is the result of calculating the second derivative of y=axn+1+bx−ny=a x^{n+1}+b x^{-n} and then multiplying by x2x^2.

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