JEE PHYSICS MCQ: WORK-ENERGY-POWER

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Application +4 | -1

A groove is in the form of a broken line

A B C

and the position vectors of the three points are respectively

2 \hat{\mathbf{i}}-3 \hat{\mathbf{j}}+2 \hat{\mathbf{k}}, 3 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}}

and

\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}

. A force of magnitude

24 \sqrt{3}

acts on a particle of unit mass kept at the point

A

and moves it along the groove to the point

C

. If the line of action of the force is parallel to the vector

\hat{\mathbf{i}}+2 \hat{\mathbf{j}}+\hat{\mathbf{k}}

all along, the number of units of work done by the force is

View answer and explanation

Correct option: C

72 \sqrt{2}

The correct answer is C (

72 \sqrt{2}

) because it is the result of calculating the work done by the force using the dot product of the force and displacement vectors.

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