Skip to main content
Back to QUADRATIC EQUATIONS

JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Medium
1 of 1
Analyzing +4 | -1
If the function f(x)=x3+3(a−7)x2+3(a2−9)x−1f\left( x \right) = {x^3} + 3\left( {a - 7} \right){x^2} + 3\left( {{a^2} - 9} \right)x - 1 has positive points of extremum then
View answer and explanation
Correct option: B
a∈(−∞,  −3)∪(3,  29/7)a \in \left( { - \infty ,\; - 3} \right) \cup \left( {3,\;29/7} \right)
Option B (a∈(−∞,  −3)∪(3,  29/7)a \in \left( { - \infty ,\; - 3} \right) \cup \left( {3,\;29/7} \right)) is correct because it satisfies the conditions for the function to have positive points of extremum.

More Questions from QUADRATIC EQUATIONS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.