The radius of $\mathrm{Li}^{+}$ion is $60 \mathrm{~pm}$ and that of $\mathrm{F}^{-}$is $136 \mathrm{~pm}$. Structure of $\mathrm{LiF}$ and coordination number is

Like $\mathrm{CsCl}, \mathrm{C} . \mathrm{Na}=8$

nti fluoride, $\mathrm{C} . \mathrm{No} .=8$

JEE CHEMISTRY MCQ: SOLID STATE

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The radius of

\mathrm{Li}^{+}

ion is

60 \mathrm{~pm}

and that of

\mathrm{F}^{-}

136 \mathrm{~pm}

. Structure of

\mathrm{LiF}

and coordination number is

View answer and explanation

Correct option: A

\mathrm{NaCl}, \mathrm{C} . \mathrm{No} .=6

Option A (Like

\mathrm{NaCl}, \mathrm{C} . \mathrm{No} .=6

) is correct because the radius ratio falls within the range that favors an

\mathrm{NaCl}

structure with a coordination number of 6.