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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Analyzing +4 | -1

If

\alpha = {\sin ^{ - 1}}\frac{{\sqrt 3 }}{2} + {\sin ^{ - 1}}\frac{1}{3}

and

\beta = {\cos ^{ - 1}}\frac{{\sqrt 3 }}{2} + {\cos ^{ - 1}}\frac{1}{3}

, then

View answer and explanation

Correct option: C

\alpha < \beta

Option C (

\alpha < \beta

) is correct because by adding the two equations, we find

\alpha + \beta = \pi

, and since

\alpha < \frac{\pi}{2}

, it follows that

\alpha < \beta

.

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\sin \left(\sin ^{-1} \frac{1}{5}+\cos ^{-1} x\right)=1

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{x^2} + {y^2} + {z^2} = {r^2},

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2{\tan ^{ - 1}}\left( {\frac{1}{3}} \right) + {\tan ^{ - 1}}\left( {\frac{1}{7}} \right)