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JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy
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Application +4 | -1
Let f:R→Rf: R \rightarrow R be a function such that f(x)=x3+x2f′(1)+xf′′(2)+f′′′(3),x∈Rf(x)=x^3+x^2 f^{\prime}(1)+x f^{\prime \prime}(2)+f^{\prime \prime \prime}(3), x \in R. Then, f(2)f(2) equals
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Correct option: B
−2-2
Option B (-2) is correct because it is the value of the function f(x) at x=2, after determining the coefficients of the polynomial.

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