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JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

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Analyzing +4 | -1

Let

f\left( x \right) = {2^{2x - 1}}

and

g\left( x \right) = - {2^x} + 2x\log 2

. Then the set of points satisfying

f'\left( x \right) > g'\left( x \right)

is

View answer and explanation

Correct option: C

\left( {0,\infty } \right)

Option C (

\left( {0,\infty } \right)

) is correct because the inequality

f'\left( x \right) > g'\left( x \right)

simplifies to

x > 0

.

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