The solution of ${\tan ^{ - 1}}2x + {\tan ^{ - 1}}3x = \frac{\pi }{4}$ is

$\left( {\frac{1}{6}, - 1} \right)$

JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

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Application +4 | -1

The solution of

{\tan ^{ - 1}}2x + {\tan ^{ - 1}}3x = \frac{\pi }{4}

View answer and explanation

Correct option: A

\frac{1}{6}

Option A (

\frac{1}{6}

) is correct because it is the only solution that satisfies the original equation after checking for extraneous roots.

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