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JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1
Let α,β\alpha ,\beta are the roots of equation 2x2−(p+1)x+(p−1)=02{x^2} - \left( {p + 1} \right)x + \left( {p - 1} \right) = 0. If α−β=αβ\alpha - \beta = \alpha \beta, then what is the value of pp?
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Correct option: B
2
Option B (2) is correct because it is the value of p that satisfies the given condition α−β=αβ\alpha - \beta = \alpha \beta.

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